delete element of a list from another list python
l1 = ["a", "b", "c", "d", "e", "f"]
l2 = ["b", "c", "e"]
l1 = [elt for elt in l1 if elt not in l2]
# l1 = ['a', 'd', 'f']delete element of a list from another list python
l1 = ["a", "b", "c", "d", "e", "f"]
l2 = ["b", "c", "e"]
l1 = [elt for elt in l1 if elt not in l2]
# l1 = ['a', 'd', 'f']python how to remove elements from a list
# Basic syntax:
my_list.remove(element)
# Note, .remove(element) removes the first matching element it finds in
# the list.
# Example usage:
animals = ['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig', 'rabbit'] # Note only 1st instance of
# rabbit was removed from the list.
# Note, if you want to remove all instances of an element, convert the
# list to a set and back to a list, and then run .remove(element) E.g.:
animals = list(set['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']))
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig']Copyright © 2021 Codeinu
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