reduce in python
'''try this'''
from functools import reduce
a = [1,2,3,4]
SUM = reduce(lambda n,n2:n+n2,a)
print(SUM)reduce in python
'''try this'''
from functools import reduce
a = [1,2,3,4]
SUM = reduce(lambda n,n2:n+n2,a)
print(SUM)javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82js reduce
// syntax: array.reduce(function, accumulator-initial-value)
let array = [3, 7, 2, 9, 5]
const result = array.reduce((accumulator, currentValue, currentIndex, arr) => {
// code
}, initialValue)
// accumulator = will store return value of the function
// currentValue = iterate through each array element
// currentIndex = index of currentValue
// arr = original array
// initialValue = set accumulator initial valuereduce()
const array1 = [1, 2, 3, 4];
const reducer = (accumulator, currentValue) => accumulator + currentValue;
// 1 + 2 + 3 + 4
console.log(array1.reduce(reducer));
// expected output: 10
// 5 + 1 + 2 + 3 + 4
console.log(array1.reduce(reducer, 5));
// expected output: 15syntax of reduce in js
[1,2,3,4,5].reduce((acc, current)=>acc+current, 0)reduce javascript
/* this is our initial value i.e. the starting point*/
const initialValue = 0;
/* numbers array */
const numbers = [5, 10, 15];
/* reducer method that takes in the accumulator and next item */
const reducer = (accumulator, item) => {
return accumulator + item;
};
/* we give the reduce method our reducer function
and our initial value */
const total = numbers.reduce(reducer, initialValue)Copyright © 2021 Codeinu
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