find the smallest number in list by comparison python
def smallest_num_in_list( list ):
min = list[ 0 ]
for a in list:
if a < min:
min = a
return minfind the smallest number in list by comparison python
def smallest_num_in_list( list ):
min = list[ 0 ]
for a in list:
if a < min:
min = a
return minCopyright © 2021 Codeinu
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