Answers for "algorithm to check if year is leap year"

5

leap year algorithm

def isLeapYear (year):
    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
		true
    else:
    	false
Posted by: Guest on February-18-2021
0

calculate if year is leap year

if (i%4==0 && i%100!=0 || i%400==0) {
months[2] = 29;
}
else {
month[2] = 28;
}
Posted by: Guest on August-06-2021

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