unique list values python ordered
def get_unique(seq):
seen = set()
seen_add = seen.add
return [x for x in seq if not (x in seen or seen_add(x))]unique list values python ordered
def get_unique(seq):
seen = set()
seen_add = seen.add
return [x for x in seq if not (x in seen or seen_add(x))]how to find unique sublist in list in python
In [22]: lst = [[1,2,3],[1,2],[1,2,3],[2,3],[4,5],[2,3],[2,4],[4,2]]
In [23]: set(frozenset(item) for item in lst)
Out[23]:
set([frozenset([2, 4]),
frozenset([1, 2]),
frozenset([2, 3]),
frozenset([1, 2, 3]),
frozenset([4, 5])])Copyright © 2021 Codeinu
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