Answers for "in list python"

python find in list

# There is several possible ways if "finding" things in lists.
'Checking if something is inside'
3 in [1, 2, 3] # => True
'Filtering a collection'
matches = [x for x in lst if fulfills_some_condition(x)]
matches = filter(fulfills_some_condition, lst)
matches = (x for x in lst if x > 6)
'Finding the first occurrence'
next(x for x in lst if ...)
next((x for x in lst if ...), [default value])
'Finding the location of an item'
[1,2,3].index(2) # => 1
[1,2,3,2].index(2) # => 1
[1,2,3].index(4) # => ValueError
[i for i,x in enumerate([1,2,3,2]) if x==2] # => [1, 3]

python list

#Creating lists
my_list = ['foo', 4, 5, 'bar', 0.4]
my_nested_list = ['foobar', ['baz', 'qux'], [0]]

#Accessing list values
my_list[2] # 5
my_list[-1] # 0.4
my_list[:2] # ['foo', 4, 5]
my_nested_list[2] # ['baz', 'quz']
my_nested_list[-1] # [0]
my_nested_list[1][1] # 'qux'

#Modifying lists
my_list.append(x) # append x to end of list
my_list.extend(iterable) # append all elements of iterable to list
my_list.insert(i, x) # insert x at index i
my_list.remove(x) # remove first occurance of x from list
my_list.pop([i]) # pop element at index i (defaults to end of list)
my_list.clear() # delete all elements from the list
my_list.index(x[, start[, end]]) # return index of element x
my_list.count(x) # return number of occurances of x in list
my_list.reverse() # reverse elements of list in-place (no return)
my_list.sort(key=None, reverse=False) # sort list in-place
my_list.copy() # return a shallow copy of the list

liste in python

Liste = ['Element1','Element2','Element3']

list in python

#list is data structure 
#used to store different types of data at same place
list = ['this is str', 12, 12.2, True]

lists in python

[0,'',True,5.2,False,[1,2]]