how to find no of times a elements in list python
thislist = (1, 3, 7, 8, 7, 5, 4, 6, 8, 5)
x = thislist.count(5)
print(x)how to find no of times a elements in list python
thislist = (1, 3, 7, 8, 7, 5, 4, 6, 8, 5)
x = thislist.count(5)
print(x)count values in array python
a = numpy.array([0, 3, 0, 1, 0, 1, 2, 1, 0, 0, 0, 0, 1, 3, 4])
unique, counts = numpy.unique(a, return_counts=True)
dict(zip(unique, counts))
# {0: 7, 1: 4, 2: 1, 3: 2, 4: 1}python how to count items in array
myArray = [1, 2, 3];
print(len(myArray));
#output
3how to count things in a list python
list.count(element)
list1 = ['red', 'green', 'blue', 'orange', 'green', 'gray', 'green']
color_count = list1.count('green')
print('The count of color: green is ', color_count)python count of values in array
import numpy as np
y = np.array([0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1])
num_zeros = (y == 0).sum()
num_ones = (y == 1).sum()Copyright © 2021 Codeinu
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