how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99]
# sort in decreasing order
my_list = sorted(my_list, reverse=True)
print(my_list)
# sort in increasing order
my_list = sorted(my_list, reverse=False)
print(my_list)
# another way to sort using built-in methods
my_list.sort(reverse=True)
print(my_list)
# sort again using slice indexes
print(my_list[::-1])
# Output
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]pythonn sort example
gList = [ "Rocket League", "Valorant", "Grand Theft Autu 5"]
gList.sort()
# OUTPUT --> ['Grand Theft Auto 5', 'Rocket League', 'Valorant']
# It sorts the list according to their namespython sort
nums = [4,8,5,2,1]
#1 sorted() (Returns sorted list)
sorted_nums = sorted(nums)
print(sorted_nums)#[1,2,4,5,8]
print(nums)#[4,8,5,2,1]
#2 .sort() (Changes original list)
nums.sort()
print(nums)#[1,2,4,5,8]python sort a list using defined order
>>> A = [[3,5],[1,3],[6,1]]
>>> B = [6,1,3]
>>> srt = {b: i for i, b in enumerate(B)}
>>> sorted(A, key=lambda x: srt[x[0]])
[[6, 1], [1, 3], [3, 5]]python sort a list by a custom order
# Example usage:
list_to_sort = [('U', 23), ('R', 42), ('L', 17, 'D')]
custom_sort_order = ['R', 'D', 'L', 'U']
sorted(list_to_sort, key=lambda list_to_sort: custom_sort_order.index(list_to_sort[0]))
# Where 0 is the tuple index to use for sorting by custom order
--> [('R', 42), ('L', 17, 'D'), ('U', 23)]Copyright © 2021 Codeinu
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