Answers for "range arguments in python"

range python 3

# range(start, stop, step)
  # start = index to begin at (INCLUSIVE)
  # stop = generate numbers up to, but not including this number (EXCLUSIVE)
  # step = (can be omitted) difference between each number in the sequence

arr = [19,5,3,22,13]

# range(stop)
for i in range(len(arr)):
    print(arr[i]) # prints: 19, 5, 3, 22, 13

# range(start, stop)
for i in range(2, len(arr)):
    print(arr[i]) # prints: 3, 22, 13
    
# range(start, stop, step)
for i in range(0, len(arr), 2):
    print(arr[i]) # prints: 19, 3, 13
    
# reverse:
for i in range(len(arr)-1, -1, -1):
    print(arr[i])

range python

range(4)        # [0, 1, 2, 3] 0 through 4, excluding 4
range(1, 4)     # [1, 2, 3] 1 through 4, excluding 4
range(1, 10, 2) # [1, 3, 5, 7, 9] 1 through 10, counting by 2s

python range in intervals of 10

print("using start, stop, and step arguments in Python range() function")
print("Printing All odd numbers between 1 and 10 using range()")
for i in range(1, 10, 2):
    print(i, end=', ')

range parameters python

arr_data=[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] 
user = int(input("Enter the product of numbers: ")) 
for i in range(0,20,1): 
    a = arr_data[i] 
    for t in range(0,20,1): 
        b = arr_data[t] 
        if (a*b) == user: 
            print(a,"x",b,"=",user) 
        else: 
            pass

range in python

for i in range (start, step, stop):
  dosomething()

python range

for i in range(0, 4):
	print(i)

>0
>1
>2
>3



for i in range(4):
	print(i)
  
>0
>1
>2
>3



for i in range(0, 4, 2):
	print(i)
    
>0
>2