Answers for "create array of size n python nmpy"

4

python declare array of size n

>>> n = 5                     #length of list
>>> list = [None] * n         #populate list, length n with n entries "None"
>>> print(list)
[None, None, None, None, None]

>>> list.append(1)            #append 1 to right side of list
>>> list = list[-n:]          #redefine list as the last n elements of list
>>> print(list)
[None, None, None, None, 1]

>>> list.append(1)            #append 1 to right side of list
>>> list = list[-n:]          #redefine list as the last n elements of list
>>> print(list)
[None, None, None, 1, 1]

>>> list.append(1)            #append 1 to right side of list
>>> list = list[-n:]          #redefine list as the last n elements of list
>>> print(list)
[None, None, 1, 1, 1]
Posted by: Guest on November-14-2020
1

python numpy array size of n

numpy.array([0] * n) #creates an int64 numpy array of size n with each element having a vaule of 0
numpy.array([0] * n, dtype = '<type>') #creates a numpy array of size n with a type of <type>
Posted by: Guest on October-07-2020

Code answers related to "create array of size n python nmpy"

Python Answers by Framework

Browse Popular Code Answers by Language