python numpy array size of n
numpy.array([0] * n) #creates an int64 numpy array of size n with each element having a vaule of 0
numpy.array([0] * n, dtype = '<type>') #creates a numpy array of size n with a type of <type>python numpy array size of n
numpy.array([0] * n) #creates an int64 numpy array of size n with each element having a vaule of 0
numpy.array([0] * n, dtype = '<type>') #creates a numpy array of size n with a type of <type>dimensions of np array python
>>> x = np.zeros((3, 5, 2), dtype=np.complex128)
>>> x.size
30
>>> np.prod(x.shape)
30numpy shape
>>> a = np.array([(1, 2), (3, 4)], dtype=[('x', 'i4'), ('y', 'i4')])
>>> np.shape(a)
(2,)
>>> a.shape
(2,)Copyright © 2021 Codeinu
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