python numpy array size of n
numpy.array([0] * n) #creates an int64 numpy array of size n with each element having a vaule of 0
numpy.array([0] * n, dtype = '<type>') #creates a numpy array of size n with a type of <type>python numpy array size of n
numpy.array([0] * n) #creates an int64 numpy array of size n with each element having a vaule of 0
numpy.array([0] * n, dtype = '<type>') #creates a numpy array of size n with a type of <type>numpy how to length of vector
>>> x = np.zeros((3, 5, 2), dtype=np.complex128)
>>> x.size
30
>>> np.prod(x.shape)
30numpy number of elements
import numpy as np
x = np.array([1,2,3], dtype=np.float64)
print("Size of the array: ", x.size)
print("Length of one array element in bytes: ", x.itemsize)
print("Total bytes consumed by the elements of the array: ", x.nbytes)Copyright © 2021 Codeinu
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