sort dictionary
#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuplessort dictionary
#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuplessort dict of dicts by key
channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'},
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'},
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'},
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'},
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'},
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'},
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}
channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
print(key, ':', value)Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
