how to round a float in python
round(number, ndigits)
how to round a float in python
round(number, ndigits)
how to round to 1 decimal place in python
# Some numerical values
valueA = 3.14159265359
valueB = 1845.7409947
valueC = -100.95
valueD = 9.5432
valueE = 34.49953
# Round to different decimal places
roundA = round(valueA, 5)
roundB = round(valueB, 4)
roundC = round(valueC, 3)
roundD = round(valueD, 2)
roundE = round(valueE, 1)
# Output rounded values
print("Value:".ljust(15), "Rounded:")
print(str(valueA).ljust(15), roundA)
print(str(valueB).ljust(15), roundB)
print(str(valueC).ljust(15), roundC)
print(str(valueD).ljust(15), roundD)
print(str(valueE).ljust(15), roundE)
python rounding numbers to n digits
def roundTraditional(val,digits):
return round(val+10**(-len(str(val))-1), digits)
round numbers python
variable.round(3)
round(variable, 3)
print('{: .3f}'.format(variable))
print("variable : %0.3f" % variable)
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