remove all integers from list python
no_integers = [x for x in mylist if not isinstance(x, int)]
remove all integers from list python
no_integers = [x for x in mylist if not isinstance(x, int)]
python how to remove elements from a list
# Basic syntax:
my_list.remove(element)
# Note, .remove(element) removes the first matching element it finds in
# the list.
# Example usage:
animals = ['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig', 'rabbit'] # Note only 1st instance of
# rabbit was removed from the list.
# Note, if you want to remove all instances of an element, convert the
# list to a set and back to a list, and then run .remove(element) E.g.:
animals = list(set['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']))
animals.remove('rabbit')
print(animals)
--> ['cat', 'dog', 'guinea pig']
python list remove at index
a = ['a', 'b', 'c', 'd']
a.pop(1)
# now a is ['a', 'c', 'd']
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