pattern in python
rows = 6 #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
for j in range(1, i - 1):
print(j, end=" ")
for j in range(i - 1, 0, -1):
print(j, end=" ")
print()pattern in python
rows = 6 #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
for j in range(1, i - 1):
print(j, end=" ")
for j in range(i - 1, 0, -1):
print(j, end=" ")
print()python regex
import re
# Regex Cheat sheet : https://www.dataquest.io/blog/regex-cheatsheet/
# Regex python tester : https://pythex.org/
# re doc : https://docs.python.org/3/library/re.html
text = "i like train"
reg = r"[a-c]" #the group of char a to c
if re.match(reg, text): #Check if regex is correct
print(text)
else:
print("Not any match")python regular expression
import re
# The string you want to find a pattern within
test_string = 'Hello greppers!'
# Creating a regular expression pattern
# This is a simple one which finds "Hello"
pattern = re.compile(r'Hello')
# This locates and returns all the occurences of the pattern
# within the test_string
match = pattern.finditer(test_string)
# Outputs all the ocurrences which were returned as
# as match objects
for match in matches:
print(match)python regular expressions example
import
re
txt = "The rain in Spain"
x = re.search("^The.*Spain$", txt)regex in python
# pip install regex
import re
# simple find all
sample = "Nothing lasts... but nothing is lost"
found = re.findall("thing", sample)
print(found)Copyright © 2021 Codeinu
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