Answers for "pyramid pattern python"

6

pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()
Posted by: Guest on December-21-2020
1

pyramid pattern in python

n = 3
for i in range(1, n+1):
  print(f"{' '*(n-i)}{' *'*i}"[1:])
  
# Output:
#  *
# * *
#* * *
Posted by: Guest on February-23-2021

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