sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)python sort based off lambda
a = sorted(a, key=lambda x: x.modified, reverse=True)python sort list in place
# Basic syntax:
your_list.sort()
# Example usage:
your_list = [42, 17, 23, 111]
your_list.sort()
print(your_list)
--> [17, 23, 42, 111]
# If you have a list of numbers that are of type string, you can do the
# following to sort them numerically without first converting to type
# int. E.g.:
your_list = ['42', '17', '23', '111']
your_list.sort(key=int)
print(your_list)
--> ['17', '23', '42', '111']
# If you want to sort a list of strings in place based on a number
# that is consistently located at some position in the strings, use
# a lambda function. E.g.:
your_list =['cmd1','cmd10', 'cmd111', 'cmd50', 'cmd99']
your_list.sort(key=lambda x: int(x[3:]))
print(your_list)
--> ['cmd1', 'cmd10', 'cmd50', 'cmd99', 'cmd111']
# If you don't want to sort the list in place, used sorted. E.g.:
your_list = [42, 17, 23, 111]
your_list_sorted = sorted(your_list)
print(your_list_sorted)
--> [17, 23, 42, 111]python lambda key sort
>>> student_tuples = [
... ('john', 'A', 15),
... ('jane', 'B', 12),
... ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2]) # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]python sorted lambda
a = ["tim", "bob", "anna", "steve", "john"]
# sorts the list by the first letter of each name
b = sorted(a, key=lambda x : x[0])
# x = each of the values in the list a
# sorts the list by length FIRST, then alphabetical order SECOND
c = sorted(a, key=lambda x : (len(x), x))sorted lambda
sorted(student_tuples, key=lambda student: student[2])Copyright © 2021 Codeinu
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