how to sort a list in python using lambda
data = [("Apples", 5, "20"), ("Pears", 1, "5"), ("Oranges", 6, "10")]
data.sort(key=lambda x:x[0])
print(data)
OUTPUT
[('Apples', 5, '20'), ('Oranges', 6, '10'), ('Pears', 1, '5')]
from kite.com
^^how to sort a list in python using lambda
data = [("Apples", 5, "20"), ("Pears", 1, "5"), ("Oranges", 6, "10")]
data.sort(key=lambda x:x[0])
print(data)
OUTPUT
[('Apples', 5, '20'), ('Oranges', 6, '10'), ('Pears', 1, '5')]
from kite.com
^^sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)python sort based off lambda
a = sorted(a, key=lambda x: x.modified, reverse=True)python lambda key sort
>>> student_tuples = [
... ('john', 'A', 15),
... ('jane', 'B', 12),
... ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2]) # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]python sort
nums = [4,8,5,2,1]
#1 sorted() (Returns sorted list)
sorted_nums = sorted(nums)
print(sorted_nums)#[1,2,4,5,8]
print(nums)#[4,8,5,2,1]
#2 .sort() (Changes original list)
nums.sort()
print(nums)#[1,2,4,5,8]python sort multiple keys
records.sort(
key = lambda l: (l[0], l[2])
)Copyright © 2021 Codeinu
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