Answers for "python dict find"

3

search in dict python

dictionary = { "key1" : 1, "name" : "Jordan", "age" : 21 }
for key in dictionary.keys():
    print("the key is {} and the value is {}".format(key, dictionary[key]))
    # or print("the key is",key,"and the value is",dictionary[key])
# OUTPOUT
# the key is key1 and the value is 1
# the key is name and the value is Jordan
# the key is age and the value is 21
Posted by: Guest on October-10-2020
0

get a value from a dictionary python

#!/usr/bin/python

dict = {'Name': 'Zabra', 'Age': 7}
print "Value : %s" %  dict.get('Age')
print "Value : %s" %  dict.get('Education', "Never")
Posted by: Guest on November-30-2020
7

get() python

# The get() method on dicts
# and its "default" argument

name_for_userid = {
    382: "Alice",
    590: "Bob",
    951: "Dilbert",
}

def greeting(userid):
    return "Hi %s!" % name_for_userid.get(userid, "there")

>>> greeting(382)
"Hi Alice!"

>>> greeting(333333)
"Hi there!"

'''When "get()" is called it checks if the given key exists in the dict.

If it does exist, the value for that key is returned.

If it does not exist then the value of the default argument is returned instead.
'''
# transferred by @ebdeuslave
# From Dan Bader - realpython.com
Posted by: Guest on April-13-2020
1

python dictionary access value by key

# Create a list of dictionary
datadict = [{'Name': 'John', 'Age': 38, 'City': 'Boston'},
 {'Name': 'Sara', 'Age': 47, 'City': 'Charlotte'},
 {'Name': 'Peter', 'Age': 63, 'City': 'London'},
 {'Name': 'Cecilia', 'Age': 28, 'City': 'Memphis'}]

# Build a function to access to list of dictionary
def getDictVal(listofdic, name, retrieve):
    for item in listofdic:
        if item.get('Name')==name:
            return item.get(retrieve)
          
 # Use the 'getDictVal' to read the data item
getDictVal(datadict, 'Sara', 'City') # Return 'Charlotte'

# -------------------
# to convert a dataframe to data dictionary
df = pd.DataFrame({'Name': ['John', 'Sara','Peter','Cecilia'],
                   'Age': [38, 47,63,28],
                  'City':['Boston', 'Charlotte','London','Memphis']})

datadict = df.to_dict('records')
Posted by: Guest on October-22-2020

Python Answers by Framework

Browse Popular Code Answers by Language