python socket send and receive

send get request python socket

import socket

target_host = "www.google.com" 
 
target_port = 80  # create a socket object 
client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)  
 
# connect the client 
client.connect((target_host,target_port))  
 
# send some data 
request = "GET / HTTP/1.1rnHost:%srnrn" % target_host
client.send(request.encode())  
 
# receive some data 
response = client.recv(4096)  
http_response = repr(response)
http_response_len = len(http_response)
 
#display the response
gh_imgui.text("[RECV] - length: %d" % http_response_len)
gh_imgui.text_wrapped(http_response)

Posted by: Guest on May-27-2020

Source

import socket HOST = '127.0.0.1' # Standard loopback interface address (localhost) PORT = 65432 # Port to listen on (non-privileged ports are > 1023) with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s: s.bind((HOST, PORT)) s.listen() conn, addr = s.accept() with conn: print('Connected by', addr) while True: data = conn.recv(1024) if not data: break conn.sendall(data)

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