Answers for "python request get url"

0

python send get request with headers

r=requests.get("http://www.example.com/", headers={"content-type":"text"})
Posted by: Guest on November-16-2020
0

python get url

import requests

URL = 'https://www.example.com'
page = requests.get(URL)
Posted by: Guest on June-03-2021
4

get requests python

import requests

r = requests.get('https://api.github.com', auth=('user', 'pass'))

print r.status_code
print r.headers['content-type']
Posted by: Guest on April-23-2020
3

python requests get

# pip install requests
import requests
req = requests.get('<url here>', 'html.parser')
print(req.text)
Posted by: Guest on April-06-2020
0

python get response from url

import requests
r = requests.get("https://google.com")
print(r.status_code)
#100- 199 Informational
#200-299 Succes
#300-399 Redirection
#400-499 CLIENT ERROR 
#500-599 SERVER ERROR
Posted by: Guest on October-09-2021

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