Answers for "requests.get(url).text"

0

python send get request with headers

r=requests.get("http://www.example.com/", headers={"content-type":"text"})
Posted by: Guest on November-16-2020
3

python requests get

# pip install requests
import requests
req = requests.get('<url here>', 'html.parser')
print(req.text)
Posted by: Guest on April-06-2020

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