Answers for "python cheat sheet pdf"

13

Python cheat sheet pdf download

Python cheatsheet, in pdf format :)
 -> https://buggyprogrammer.com/python-cheat-sheet/
Posted by: Guest on May-18-2021
7

python cheat sheet

Best Python Cheat Sheet PDF:
https://websitesetup.org/wp-content/uploads/2020/04/Python-Cheat-Sheet.pdf
Posted by: Guest on January-04-2021
0

python codes and answers cheat code pdf

def increment(number, by=1):   
    return number + by
 
# Keyword arguments 
increment(2, by=1)
 
# Variable number of arguments 
def multiply(*numbers): 
    for number in numbers: 
        print number 
 
 
multiply(1, 2, 3, 4)
 
# Variable number of keyword arguments 
def save_user(**user):  
    ...
 
 
save_user(id=1, name="Mosh")
Posted by: Guest on November-28-2020
0

python codes and answers cheat code pdf

a = 1       # integer
b = 1.1     # float
c = 1 + 2j  # complex number (a + bi)
d = “a”     # string
e = True    # boolean (True / False)
Posted by: Guest on November-28-2020
0

python codes and answers cheat code pdf

if x == 1:  
    print(“a”)
elif x == 2:  
    print(“b”)
else:   
    print(“c”)
 
# Ternary operator 
x = “a” if n > 1 else “b”
 
# Chaining comparison operators
if 18 <= age < 65:
Posted by: Guest on November-28-2020
0

python codes and answers cheat code pdf

# Creating lists
letters = ["a", "b", "c"]     
matrix = [[0, 1], [1, 2]]
zeros = [0] * 5
combined = zeros + letters
numbers = list(range(20))
 
# Accessing items
letters = ["a", "b", "c", "d"]
letters[0]  # "a"
letters[-1] # "d"
 
# Slicing lists 
letters[0:3]   # "a", "b", "c"
letters[:3]    # "a", "b", "c"
letters[0:]    # "a", "b", "c", "d"
letters[:]     # "a", "b", "c", "d"
letters[::2]   # "a", "c"
letters[::-1]  # "d", "c", "b", "a" 
 
# Unpacking 
first, second, *other = letters 
 
# Looping over lists 
for letter in letters: 
    ... 
 
for index, letter in enumerate(letters): 
    ... 
 
# Adding items 
letters.append("e")
letters.insert(0, "-")
 
# Removing items 
letters.pop()
letters.pop(0)
letters.remove("b")
del letters[0:3]
 
# Finding items 
if "f" in letters: 
    letters.index("f")
 
# Sorting lists 
letters.sort()
letters.sort(reverse=True) 
 
# Custom sorting 
items = [
    ("Product1", 10),
    ("Product2", 9),
    ("Product3", 11)
]
 
items.sort(key=lambda item: item[1])
 
# Map and filter 
prices = list(map(lambda item: item[1], items))
expensive_items = list(filter(lambda item: item[1] >= 10, items))
 
# List comprehensions 
prices = [item[1] for item in items]
expensive_items = [item for item in items if item[1] >= 10]
 
# Zip function 
list1 = [1, 2, 3]
list2 = [10, 20, 30]
combined = list(zip(list1, list2))    # [(1, 10), (2, 20)]
Posted by: Guest on November-28-2020

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