Answers for "tic tac toe game ai python"

1

tic tac toe python

def slant_check(matrix,P1,P2):
    empty_lst1 = []
    empty_lst2= []
    lst1 = []
    lst2 = []
    x = len(matrix)
    v = len(matrix) - 1
    t = 0 
    g = 0
    n = True
    while n:
        for i in range(x):
            if matrix[i][i] == P1 or matrix[t][i] == P1:
                empty_lst1.append(matrix[i][i])
            if matrix[i][i] == P2 or matrix[t][i] == P2:
                empty_lst2.append(matrix[i][i])
        while v >= g:
            if matrix[g][v] == P1:
                lst1.append(matrix[g][v]) 
            if matrix[g][v] == P2:
                lst2.append(matrix[g][v])
            t -= 1
            v -= 1
            g += 1
        if len(empty_lst1) == x:
            return True
        if len(empty_lst2) == x:
            return True
        if len(lst1) == x:
            return True
        if len(lst2) == x:
            return True
        return False
def vertical_check(lst,P1,P2):
    for i in range(len(lst) - 2):
        for j in range(len(lst)):
            if lst[i][j] == P1 and lst[i + 1][j] == P1 and lst[i + 2][j] == P1:
                return True
            if lst[i][j] == P2 and lst[i + 1][j] == P2 and lst[i + 2][j] == P2:
                return True
            
    return False
def horizontal_check(lst,P1,P2):
    for i in range(len(lst)):
        for j in range(len(lst) - 2):
            if lst[i][j]== P1 and lst[i][j + 1]== P1 and lst[i][j + 2]== P1 :
                return True
            if lst[i][j]== P2 and lst[i][j + 1]== P2 and lst[i][j + 2]== P2 :
                return True
    return False
def find_grid2(place,lst):
    for i in range(len(lst)):
        for j in range(len(lst[i])):
            if place == lst[i][j]:
                return lst.index(lst[i])

def find_grid1(place,lst):
    for i in range(len(lst)):
        for j in range(len(lst[i])):
            if place == lst[i][j]:
                return lst[i].index(place)
            
def print_lst(lst):
    for i in range(len(lst)):
        for j in range(len(lst[i]) - 2):
            print(lst[i][j],'|', lst[i][j + 1],'|', lst[i][j + 2])
            print('----------')
def tic_tac_toe():
    lst = [[1,2,3],
           [4,5,6],
           [7,8,9]]
    P1 = 0
    P2 = 0
    counter_loop = 0
    _ = 0 
    new_lst = [1,2]
    while True:
        P1 = input('Player1 select "x" or "o" ? (Type in x or o):n').lower()
        if P1 == 'x':
            print('Player2 is now "o"!n')
            P2 = 'o'
            break
        if P1 == 'o':
            print('Player2 is now "x"!n')
            P2 = 'x'
            break
        else:
            print('Try Againn')
    print_lst(lst)
    while _ < len(lst): 
        for i in range(len(lst[_])):
            if counter_loop == 9:
                print("Tie!")
                break
            place_grid1 = input('Where would Player 1 like to place? : ')
            if int(place_grid1) >= 10 or int(place_grid1) <= 0:
                print('Try Again')
                place_grid1 = input('Where would Player 1 like to place? : ')
                break
            place_grid = int(place_grid1)
            counter_loop += 1
            inner_index1 = find_grid1(place_grid,lst)
            outer_index1 = find_grid2(place_grid,lst)
            lst[outer_index1][inner_index1] = P1
            print_lst(lst)
            if horizontal_check(lst,P1,P2) == True:
                print("Player 1 wins!!")
                counter_loop = 9 
                break
            if vertical_check(lst,P1,P2) == True:
                print("Player 1 wins!!")
                counter_loop = 9 
                break
            if slant_check(lst,P1,P2) == True:
                print("Player 1 wins!!")
                counter_loop = 9 
                break
            if counter_loop == 9:
                print("Tie!")
                break
            place_grid2 = input('Where would Player 2 like to place? : ')
            if int(place_grid2) >= 10 or int(place_grid2) <=0:
                print('Try Again')
                place_grid2 = input('Where would Player 2 like to place? : ')
                break
            place_gridy = int(place_grid2)
            counter_loop += 1
            inner_index2 = find_grid1(place_gridy,lst)
            outer_index2 = find_grid2(place_gridy,lst)
            lst[outer_index2][inner_index2] = P2
            print_lst(lst)
            if horizontal_check(lst,P1,P2) == True:
                print("Player 2 wins!!")
                counter_loop = 9 
                break
            if vertical_check(lst,P1,P2) == True:
                print("Player 2 wins!!")
                counter_loop = 9 
                break
            if slant_check(lst,P1,P2) == True:
                print("Player 2 wins!!")
                counter_loop = 9 
                break
            if counter_loop == 9:
                print("Tie!")
                break        
        if counter_loop == 9:
            break
        
        _ += 1

    
tic_tac_toe()
Posted by: Guest on August-26-2020
0

tic tac toe algorithm python

#algorithim for X player
#python 3.85


import random


def algoX(lisp):
  '''my bacic stupid idiotic dunder-headded ape-brained algorithim'''
  
  for i in range(len(lisp)):
    if lisp[i] == 1:
      lisp[i] = 'X'
    elif lisp[i] == 2:
      lisp[i] = 'O'
  
  def zeros(list):
    out = 0
    for i in range(len(list)):
      if list[i] == 0:
        out += 1
    return out
  
  def count(list, simb):
    out = 0
    for i in range(len(list)):
      if list[i] == simb:
        out += 1
    return out
  
  if count(lisp[0:3], 'X') == 2 and zeros(lisp[0:3]) == 1:
    lisp[0:3] = 'X','X','X'
  
  elif count(lisp[3:6], 'X') == 2 and zeros(lisp[3:6]) == 1:
    lisp[3:6] = 'X','X','X'
  
  elif count(lisp[6:9], 'X') == 2 and zeros(lisp[6:9]) == 1:
    lisp[6:9] = 'X','X','X'
    
  elif count([lisp[0],
              lisp[3],
              lisp[6]],'X') == 2 and zeros([lisp[0],lisp[3],lisp[6]]) == 1:
    for i in range(3):
      lisp[i*3] = 'X'
  
  elif count([lisp[1],
              lisp[4],
              lisp[7]],'X') == 2 and zeros([lisp[1],lisp[4],lisp[7]]) == 1:
    for i in range(3):
      lisp[(i*3)+1] = 'X'
  
  elif count([lisp[2],
              lisp[5],
              lisp[8]],'X') == 2 and zeros([lisp[2],lisp[5],lisp[8]]) == 1:
    for i in range(3):
      lisp[(i*3)+2] = 'X'
      
  elif count([lisp[0],
              lisp[4],
              lisp[8]],'X') == 2 and zeros([lisp[0],lisp[4],lisp[8]]) == 1:
    for i in range(3):
      lisp[(i*4)] = 'X'
  
  elif count([lisp[2],
              lisp[4],
              lisp[6]],'X') == 2 and zeros([lisp[2],lisp[4],lisp[6]]) == 1:
    
    lisp[2], lisp[4], lisp[6] = 'X','X','X'
  
  else:
    '''prevent loss'''
    if count(lisp[0:3], 'O') == 2 and zeros(lisp[0:3]) == 1:
      for i in range(3):
        if lisp[i] == 0:
          lisp[i] = 'X'
    
    elif count(lisp[3:6], 'O') == 2 and zeros(lisp[3:6]) == 1:
      for i in range(3,6):
        if lisp[i] == 0:
          lisp[i] = 'X'
    
    elif count(lisp[6:9], 'O') == 2 and zeros(lisp[6:9]) == 1:
      for i in range(6,9):
        if lisp[i] == 0:
          lisp[i] = 'X'
    
    elif count([lisp[0],
                lisp[3],
                lisp[6]],'O') == 2 and zeros([lisp[0],lisp[3],lisp[6]]) == 1:
      for i in range(3):
        if lisp[i*3] == 0:
          lisp[i*3] = 'X'
          
    elif count([lisp[1],
              lisp[4],
              lisp[7]],'X') == 2 and zeros([lisp[1],lisp[4],lisp[7]]) == 1:
      for i in range(3):
        if lisp[(i*3)+1] == 0:
          lisp[(i*3)+1] = 'X'
    
    elif count([lisp[2],
              lisp[5],
              lisp[8]],'X') == 2 and zeros([lisp[2],lisp[5],lisp[8]]) == 1:
      for i in range(3):
        if lisp[(i*3)+2] == 0:
          lisp[(i*3)+2] = 'X'
    
    elif count([lisp[0],
              lisp[4],
              lisp[8]],'X') == 2 and zeros([lisp[0],lisp[4],lisp[8]]) == 1:
      for i in range(3):
        if lisp[i*4] == 0:
          lisp[(i*4)] = 'X'
    
    elif count([lisp[2],
              lisp[4],
              lisp[6]],'X') == 2 and zeros([lisp[2],lisp[4],lisp[6]]) == 1:
      if lisp[2] == 0:
        lisp[2] = 'X'
        
      elif lisp[4] == 0:
        lisp[4] = 'X'
        
      elif lisp[6] == 0:
        lisp[6] = 'X'
    
    else:
      '''regular options'''
      if lisp[4] == 0:
        lisp[4] = 'X'
      else:
        while True:
          rand = random.randint(0,8)
          if lisp[rand] == 'X' or lisp[rand] == 'O':
            continue
          else:
            lisp[rand] = 'X'
            break
     
    
          
      
    
        
  return lisp
Posted by: Guest on October-19-2020

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