python pop element
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed
#(first element is 0)how to pop things out of list python
>>> l = ['a', 'b', 'c', 'd']
>>> l.pop(0)
'a'
>>> l
['b', 'c', 'd']python list pop
# Python pop list
some_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # normal python list
print(some_list) # prints [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
some_list.pop() # pop() is used to pop out one index from a list (default index in pop is -1)
print(some_list) # prints [1, 2, 3, 4, 5, 6, 7, 8, 9]
=====================================================
# Output:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9]python list pop equivalent
# Python pop() equivalent
mylist = ['a', 'b', 'c', 'd', 'e']
# remove 'b'
mylist = mylist[:1] + mylist[1+1:]
# return ['a', 'c', 'd', 'e']
A = 0
A, mylist = A + 9, mylist[:1] + mylist[1+1:]
# return 9 ['a', 'd', 'e']python list safely pop
In [1]: from typing import List, Any
In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
...: try:
...: return input_list.pop(index)
...: except IndexError:
...: return default_value
...:
# list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)
In [5]: y
Out[5]: 100
# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0python list.pop()
my_list = [1,2,3,4]
# Default pop
my_list.pop()
print(f'Default : {my_list}')
# Index pop
my_list.pop(1)
print(f'By Index : {my_list}')Copyright © 2021 Codeinu
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