python pop element
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed
#(first element is 0)how to pop things out of list python
>>> l = ['a', 'b', 'c', 'd']
>>> l.pop(0)
'a'
>>> l
['b', 'c', 'd']python list safely pop
In [1]: from typing import List, Any
In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
...: try:
...: return input_list.pop(index)
...: except IndexError:
...: return default_value
...:
# list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)
In [5]: y
Out[5]: 100
# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0Copyright © 2021 Codeinu
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