Answers for "how to check for a prime number in python"

7

determine if number is prime python

# Time Efficient Primality Check in Python

def primeCheck(n):
    # 0, 1, even numbers greater than 2 are NOT PRIME
    if n==1 or n==0 or (n % 2 == 0 and n > 2):
        return "Not prime"
    else:
        # Not prime if divisable by another number less
        # or equal to the square root of itself.
        # n**(1/2) returns square root of n
        for i in range(3, int(n**(1/2))+1, 2):
            if n%i == 0:
                return "Not prime"
        return "Prime"
Posted by: Guest on September-17-2020
1

is prime python

import math
def isPrimeNumber(n):
    if (n < 2):
        return False;
    sq = int(math.sqrt(n))
    for i in range(2, sq + 1):
        if (n % i == 0):
            return False
    return True
Posted by: Guest on October-29-2021
2

get prime number python

from num_tool import is_prime
print(is_prime(3))

#returns True because 3 is a prime
Posted by: Guest on September-13-2021
0

python prime check

def isPrime(n):
  if n<2:		#1, 0 and all negative numbers are not prime
    return False
  elif n==2:	#2 is prime but cannot be calculated with the formula below becuase of the range function
    return True
  else:
    for i in range(2, n):
      if (n % i) == 0:	#if you can precisely divide a number by another number, it is not prime
        return False
    return True			#if the progam dont return False and arrives here, it means it has checked all the numebrs smaller than n and nono of them divides n. So n is prime
Posted by: Guest on March-26-2021
0

how to see if a number is prime in python

def is_prime(n: int) -> bool:
    """Primality test using 6k+-1 optimization."""
    if n <= 3:
        return n > 1
    if n % 2 == 0 or n % 3 == 0:
        return False
    i = 5
    while i ** 2 <= n:
        if n % i == 0 or n % (i + 2) == 0:
            return False
        i += 6
    return True
Posted by: Guest on June-02-2021

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