is prime python
import math
def isPrimeNumber(n):
if (n < 2):
return False;
sq = int(math.sqrt(n))
for i in range(2, sq + 1):
if (n % i == 0):
return False
return True
is prime python
import math
def isPrimeNumber(n):
if (n < 2):
return False;
sq = int(math.sqrt(n))
for i in range(2, sq + 1):
if (n % i == 0):
return False
return True
python prime check
def isPrime(n):
if n<2: #1, 0 and all negative numbers are not prime
return False
elif n==2: #2 is prime but cannot be calculated with the formula below becuase of the range function
return True
else:
for i in range(2, n):
if (n % i) == 0: #if you can precisely divide a number by another number, it is not prime
return False
return True #if the progam dont return False and arrives here, it means it has checked all the numebrs smaller than n and nono of them divides n. So n is prime
how to check if a number is prime in python
import math
def prime(x):
if x == 2 or x == 3 or x==5:
return True
if x == 1 or x == 4:
return False
num = 2
a= math.sqrt(x)+4
while a > num:
if x % num == 0:
return False
else:
num = num + 1
return True
prime checker in python
#make the function
#to do this all hte vairibles go in side the function
def CheckIfPrime ():
a1 = input("which number do you want to check")
a = int(a1)#you need the checking number as an int not an str
b = 2 #the number to check againts
c = ("yes")
while b < a:#run the loop
if a%b == 0:#check if the division has a remainder
c = ("no")#set the answer
b = b+1
print(c)#print the output
CheckIfPrime ()#call the function
how to see if a number is prime in python
def is_prime(n: int) -> bool:
"""Primality test using 6k+-1 optimization."""
if n <= 3:
return n > 1
if n % 2 == 0 or n % 3 == 0:
return False
i = 5
while i ** 2 <= n:
if n % i == 0 or n % (i + 2) == 0:
return False
i += 6
return True
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