datediff in seconds in pandas
t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')
print pd.Timedelta(t2 - t1).seconds / 3600.0datediff in seconds in pandas
t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')
print pd.Timedelta(t2 - t1).seconds / 3600.0python: calculate number of days from today date in a data frame
df[['A','B']] = df[['A','B']].apply(pd.to_datetime) # If conversion required
df['C'] = (df['B'] - df['A']).dt.daysCopyright © 2021 Codeinu
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