Answers for "Output the minimum time difference between column1 and Column2 using pandas."

datediff in seconds in pandas

t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')

print pd.Timedelta(t2 - t1).seconds / 3600.0

Posted by: Guest on January-19-2021

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