Answers for "how to find most repeated number in an array python"

1

Pack consecutive duplicates of list elements into sublists python

import itertools

def pack_consecutive_duplicates(_list: list):
    preprocessed_list = []
    # x groups the duplicates into a tuple ()
    # x[0] is the duplicate element
    # x[1] is a grouper iterable that conatins all the duplicate elements
    for x in itertools.groupby(_list):
        amount = [*x[1]].count(x[0])
        if amount > 1:
            for k in range(0, amount):
                preprocessed_list.append(x[0])
        else:
            preprocessed_list.append((x[0]))

    return preprocessed_list
Posted by: Guest on February-23-2020
0

find duplicates in list python

def Find_Repeated(x):
    x2=sorted(x)
    List_Of_Repeated=[]
    for i in x2:
        if x2.count(i)>1:
            List_Of_Repeated.append([i,x2.count(i)])
            for c in range(x2.count(i)):
                for j in x2:
                    if i==j and x2.count(i)>1:
                        x2.remove(i)
    List_Of_Repeated.sort()
    return List_Of_Repeated

List=[1,2,3,4,4,4,5,5,5,5,5,1,1,2,2,3,7,8,6]

# Repeated numbers: [1,2,3,4,5]

# Simple print output:

print(Find_Repeated(List),"n")

# For a neat output:

print("[ Value , Times Repeated ] n")
print("For example: [2,4]  The value 2 was repeated 4 times. n")
for i in Find_Repeated(List):
    print(i)
Posted by: Guest on September-17-2020

Code answers related to "how to find most repeated number in an array python"

Python Answers by Framework

Browse Popular Code Answers by Language