Answers for "check for duplicate entries in list"

1

duplicate in list python

a = [1,2,3,2,1,5,6,5,5,5]

import collections
print([item for item, count in collections.Counter(a).items() if count > 1])

## [1, 2, 5]
Posted by: Guest on May-21-2020
0

program to print duplicates from a list of integers in python

lst = [ 3, 6, 9, 12, 3, 30, 15, 9, 45, 36, 12, 12]
dupItems = []
uniqItems = {}
for x in lst:
   if x not in uniqItems:
      uniqItems[x] = 1
   else:
      if uniqItems[x] == 1:
         dupItems.append(x)
      uniqItems[x] += 1
print(dupItems)
Posted by: Guest on December-21-2020
0

find duplicates in list python

def Find_Repeated(x):
    x2=sorted(x)
    List_Of_Repeated=[]
    for i in x2:
        if x2.count(i)>1:
            List_Of_Repeated.append([i,x2.count(i)])
            for c in range(x2.count(i)):
                for j in x2:
                    if i==j and x2.count(i)>1:
                        x2.remove(i)
    List_Of_Repeated.sort()
    return List_Of_Repeated

List=[1,2,3,4,4,4,5,5,5,5,5,1,1,2,2,3,7,8,6]

# Repeated numbers: [1,2,3,4,5]

# Simple print output:

print(Find_Repeated(List),"n")

# For a neat output:

print("[ Value , Times Repeated ] n")
print("For example: [2,4]  The value 2 was repeated 4 times. n")
for i in Find_Repeated(List):
    print(i)
Posted by: Guest on September-17-2020

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