python count repeated elements in a list
# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}
# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}count the duplicates in a list in python
some_list=['a','b','c','b','d','m','n','n']
my_list=sorted(some_list)
duplicates=[]
for i in my_list:
if my_list.count(i)>1:
if i not in duplicates:
duplicates.append(i)
print(duplicates)duplicate in list python
a = [1,2,3,2,1,5,6,5,5,5]
import collections
print([item for item, count in collections.Counter(a).items() if count > 1])
## [1, 2, 5]find duplicates in list python
def Find_Repeated(x):
x2=sorted(x)
List_Of_Repeated=[]
for i in x2:
if x2.count(i)>1:
List_Of_Repeated.append([i,x2.count(i)])
for c in range(x2.count(i)):
for j in x2:
if i==j and x2.count(i)>1:
x2.remove(i)
List_Of_Repeated.sort()
return List_Of_Repeated
List=[1,2,3,4,4,4,5,5,5,5,5,1,1,2,2,3,7,8,6]
# Repeated numbers: [1,2,3,4,5]
# Simple print output:
print(Find_Repeated(List),"n")
# For a neat output:
print("[ Value , Times Repeated ] n")
print("For example: [2,4] The value 2 was repeated 4 times. n")
for i in Find_Repeated(List):
print(i)Copyright © 2021 Codeinu
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