Answers for "key=lambda python"

4

sorted python lambda

lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)
Posted by: Guest on June-23-2020
24

python lambda

multiply = lambda x,y: x * y
multiply(21, 2) #42
#_____________
def myfunc(n):
  return lambda a : a * n

mydoubler = myfunc(2)
print(mydoubler(11)) #22
Posted by: Guest on May-09-2020
4

python lambda key sort

>>> student_tuples = [
...     ('john', 'A', 15),
...     ('jane', 'B', 12),
...     ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2])   # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
Posted by: Guest on May-23-2020

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