python find factors of a number
def factors(n):
return set(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if not n % i )))python find factors of a number
def factors(n):
return set(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if not n % i )))quick way to find the factor of a number python
def factors(x):
listOfFactors = []
for i in range(1, int(x ** 0.5)):
# Use a loop from 1 to the square root of x for more speed.
if x % i == 0:
listOfFactors.append(x)
listOfFactors.append(i)
# May repeat some numbers. Further code would be needed to fix that.
print(i)Copyright © 2021 Codeinu
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