python merge list of dict into single dict
l = [{'a': 0}, {'b': 1}, {'c': 2}, {'d': 3}, {'e': 4, 'a': 4}]
d = {k: v for x in l for k, v in x.items()}
print(d)
# {'a': 4, 'b': 1, 'c': 2, 'd': 3, 'e': 4}python merge list of dict into single dict
l = [{'a': 0}, {'b': 1}, {'c': 2}, {'d': 3}, {'e': 4, 'a': 4}]
d = {k: v for x in l for k, v in x.items()}
print(d)
# {'a': 4, 'b': 1, 'c': 2, 'd': 3, 'e': 4}python join dict
def mergeDict(dict1, dict2):
''' Merge dictionaries and keep values of common keys in list'''
dict3 = {**dict1, **dict2}
for key, value in dict3.items():
if key in dict1 and key in dict2:
dict3[key] = [value , dict1[key]]
return dict3
# Merge dictionaries and add values of common keys in a list
dict3 = mergeDict(dict1, dict2)
print('Dictionary 3 :')
print(dict3)merge a list of dictionaries python
>>> from collections import ChainMap
>>> a = [{'a':1},{'b':2},{'c':1},{'d':2}]
>>> dict(ChainMap(*a))
{'b': 2, 'c': 1, 'a': 1, 'd': 2}concat dicts python
d1={1:2,3:4}; d2={5:6,7:9}; d3={10:8,13:22}
d4 = dict(d1, **d2); d4.update(d3)Copyright © 2021 Codeinu
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