Answers for "open path python"

python file from path

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

python open file relative to script location

import os

path = 'a/relative/file/path/to/this/script/file.txt'

with open(os.path.join(os.path.dirname(__file__), path), 'r') as input_file:
    content = input_file.read()

path in python

data_folder = "source_data/text_files/"

file_to_open = data_folder + "raw_data.txt"

f = open(file_to_open)

print(f.read())