python super init
class test:
def __init__(self, *args):
print(f"called test with: {args}")
class testing(test):
def __init__(self, *args):
print(f"Called testing with: {args}")
super().__init__(*args)
testing("hmm")
# super is a keyword that calls the parent classpython super
# It's kinda hard to explain this just by code.
# So I'll provide a link to a pretty good explanation of it.
https://www.pythonforbeginners.com/super/working-python-super-functionhow to get the parent class using super python
class Foo(Bar):
def __init__(self, *args, **kwargs):
# invoke Bar.__init__
super().__init__(*args, **kwargs)python super
class Square(Rectangle):
def __init__(self, length):
super().__init__(length, length)python why call super(class).__init__()
super() lets you avoid referring to the base class explicitly,
which can be nice.
But the main advantage comes with multiple inheritance.
Note that the syntax changed in Python 3.0: you can just say super().__init__()
instead of super(ChildB, self).__init__() which IMO is quite a bit nicer.Copyright © 2021 Codeinu
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