Answers for "super.__init__()"

python super init

class test:
  def __init__(self, *args):
    print(f"called test with: {args}")

class testing(test):
  def __init__(self, *args):
    print(f"Called testing with: {args}")
    super().__init__(*args)
        
testing("hmm")
# super is a keyword that calls the parent class

python super

# It's kinda hard to explain this just by code.
# So I'll provide a link to a pretty good explanation of it.
https://www.pythonforbeginners.com/super/working-python-super-function

how to get the parent class using super python

class Foo(Bar):

    def __init__(self, *args, **kwargs):
        # invoke Bar.__init__
        super().__init__(*args, **kwargs)

python super

class Square(Rectangle):
    def __init__(self, length):
        super().__init__(length, length)

python why call super(class).__init__()

super() lets you avoid referring to the base class explicitly, 
which can be nice. 
But the main advantage comes with multiple inheritance.
Note that the syntax changed in Python 3.0: you can just say super().__init__()
instead of super(ChildB, self).__init__() which IMO is quite a bit nicer.