Answers for "urllib3 for python 2.7"

1

urllib3 python

>>> import urllib3
>>> http = urllib3.PoolManager()
>>> r = http.request('GET', 'http://httpbin.org/robots.txt')
>>> r.status
200
>>> r.data
'User-agent: *nDisallow: /denyn'
Posted by: Guest on August-13-2020

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