Answers for "urllib.request python3"

1

urllib3 python

>>> import urllib3
>>> http = urllib3.PoolManager()
>>> r = http.request('GET', 'http://httpbin.org/robots.txt')
>>> r.status
200
>>> r.data
'User-agent: *nDisallow: /denyn'
Posted by: Guest on August-13-2020
-1

with urllib.request.urlopen("https://

import urllib.request

req = urllib.request.Request('http://www.voidspace.org.uk')
with urllib.request.urlopen(req) as response:
   the_page = response.read()
Posted by: Guest on April-16-2020

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