Answers for "Open API using urllib3"

1

how to urllib3

>>> import urllib3
>>> http = urllib3.PoolManager()
>>> r = http.request('GET', 'http://httpbin.org/robots.txt')
>>> r.status
200
>>> r.data
'User-agent: *nDisallow: /denyn'
Posted by: Guest on August-13-2020

Python Answers by Framework

Browse Popular Code Answers by Language