Answers for "pandas find row by index name"

2

pandas select row by index

#for single row
df.loc[ index , : ]

# for multiple rows
indices = [1, 20, 33, 47, 52 ]
new_df= df.iloc[indices, :]
Posted by: Guest on April-10-2021
2

dataframe get row by name

row_data = df.loc[ 'a' , : ]
Posted by: Guest on April-03-2020
2

isolate row based on index pandas

dfObj.iloc[: , [0, 2]]
Posted by: Guest on March-30-2020
0

dataframe select row by index value

In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))

In [2]: df
Out[2]: 
          A         B
0  1.068932 -0.794307
2 -0.470056  1.192211
4 -0.284561  0.756029
6  1.037563 -0.267820
8 -0.538478 -0.800654

In [5]: df.iloc[[2]]
Out[5]: 
          A         B
4 -0.284561  0.756029

In [6]: df.loc[[2]]
Out[6]: 
          A         B
2 -0.470056  1.192211
Posted by: Guest on April-08-2020

Python Answers by Framework

Browse Popular Code Answers by Language