Answers for "dictionary in python"

109

python dictionary

#Creating dictionaries
dict1 = {'color': 'blue', 'shape': 'square', 'volume':40}
dict2 = {'color': 'red', 'edges': 4, 'perimeter':15}

#Creating new pairs and updating old ones
dict1['area'] = 25 #{'color': 'blue', 'shape': 'square', 'volume': 40, 'area': 25}
dict2['perimeter'] = 20 #{'color': 'red', 'edges': 4, 'perimeter': 20}

#Accessing values through keys
print(dict1['shape'])

#You can also use get, which doesn't cause an exception when the key is not found
dict1.get('false_key') #returns None
dict1.get('false_key', "key not found") #returns the custom message that you wrote 

#Deleting pairs
dict1.pop('volume')

#Merging two dictionaries
dict1.update(dict2) #if a key exists in both, it takes the value of the second dict
dict1 #{'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20}

#Getting only the values, keys or both (can be used in loops)
dict1.values() #dict_values(['red', 'square', 25, 4, 20])
dict1.keys() #dict_keys(['color', 'shape', 'area', 'edges', 'perimeter'])
dict1.items() 
#dict_items([('color', 'red'), ('shape', 'square'), ('area', 25), ('edges', 4), ('perimeter', 20)])
Posted by: Guest on May-20-2020
6

dictionary in python

tel = {'jack': 4098, 'sape': 4139}
tel['guido'] = 4127
print(tel)
# OUTPUT {'jack': 4098, 'sape': 4139, 'guido': 4127}
print(tel['jack'])
# OUTPUT 4098
del tel['sape']
tel['irv'] = 4127
print(tel)
# OUTPUT {'jack': 4098, 'guido': 4127, 'irv': 4127}
print(list(tel))
# OUTPUT ['jack', 'guido', 'irv']
print(sorted(tel))
# OUTPUT ['guido', 'irv', 'jack']
print('guido' in tel)
# OUTPUT True
print('jack' not in tel)
# OUTPUT False
Posted by: Guest on March-04-2021

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