printing python dictionary values
#print keys and values from the dictionary for k, v in dic.items(): print(k, v)
printing python dictionary values
#print keys and values from the dictionary for k, v in dic.items(): print(k, v)
python dictionary
#Creating dictionaries dict1 = {'color': 'blue', 'shape': 'square', 'volume':40} dict2 = {'color': 'red', 'edges': 4, 'perimeter':15} #Creating new pairs and updating old ones dict1['area'] = 25 #{'color': 'blue', 'shape': 'square', 'volume': 40, 'area': 25} dict2['perimeter'] = 20 #{'color': 'red', 'edges': 4, 'perimeter': 20} #Accessing values through keys print(dict1['shape']) #You can also use get, which doesn't cause an exception when the key is not found dict1.get('false_key') #returns None dict1.get('false_key', "key not found") #returns the custom message that you wrote #Deleting pairs dict1.pop('volume') #Merging two dictionaries dict1.update(dict2) #if a key exists in both, it takes the value of the second dict dict1 #{'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20} #Getting only the values, keys or both (can be used in loops) dict1.values() #dict_values(['red', 'square', 25, 4, 20]) dict1.keys() #dict_keys(['color', 'shape', 'area', 'edges', 'perimeter']) dict1.items() #dict_items([('color', 'red'), ('shape', 'square'), ('area', 25), ('edges', 4), ('perimeter', 20)])
dictionary in python
# Dictionaries in Python ages = {"John": 43, "Bob": 24, "Ruth": 76} # Marked by { at beginning and a } at end # ^^^ Has sets of keys and values, like the 'John' and 43 set. These two values must be seperated by a colon # ^^^ Sets of values seperated by commas.
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