Answers for "check if the string phone start with string start and print the result hackerrank"

find a string hackereank

def count_substring(string, sub_string):
    count=0  #initialise count variable
    for i in range(0,len(string)):
        if string[i:].startswith(sub_string): # basically it traverses from left to right and looks for occurence of substring
            count+=1 #every time count will increase by 1

    return count

Posted by: Guest on July-01-2020

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Answers for "check if the string phone start with string start and print the result hackerrank"

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Answers for "check if the string phone start with string start and print the result hackerrank"

Code answers related to "check if the string phone start with string start and print the result hackerrank"

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