python initialize a 2d array
x = [[foo for i in range(10)] for j in range(10)]
# x is now a 10x10 array of 'foo' (which can depend on i and j if you want)python initialize a 2d array
x = [[foo for i in range(10)] for j in range(10)]
# x is now a 10x10 array of 'foo' (which can depend on i and j if you want)how to create 2d list in python
o=[]
for i in range(0,rows):
x=[]
for j in range(0,cols):
x.append(0)
o.append(x)
#if you use [[0]*cols]*rows all rows will become the same list
#so editing in one row will edit all rows2d array python initialize
>>> b = [['a']*3]*3
>>> b
[['a', 'a', 'a'], ['a', 'a', 'a'], ['a', 'a', 'a']]
>>> b[1][1]
'a'
>>> b[1][1] = 'b'
>>> b
[['a', 'b', 'a'], ['a', 'b', 'a'], ['a', 'b', 'a']]initialise a 2d array python
x = [[foo for i in range(10)] for j in range(10)]
# x is now a 10x10 array of 'foo' (which can depend on i and j if you want)python initialize a 2d array
bar = [SOME EXPRESSION for item in some_iterable]python 2d matrix declare
length, breadth = x, y
matrix = [[-1 for j in range(breadth)] for i in range(length)]
# every element is -1Copyright © 2021 Codeinu
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