sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)
sorted python lambda
lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)
how to sort a list in python using lambda
data = [("Apples", 5, "20"), ("Pears", 1, "5"), ("Oranges", 6, "10")]
data.sort(key=lambda x:x[0])
print(data)
OUTPUT
[('Apples', 5, '20'), ('Oranges', 6, '10'), ('Pears', 1, '5')]
from kite.com
^^
python sorted lambda
a = ["tim", "bob", "anna", "steve", "john"]
# sorts the list by the first letter of each name
b = sorted(a, key=lambda x : x[0])
# x = each of the values in the list a
# sorts the list by length FIRST, then alphabetical order SECOND
c = sorted(a, key=lambda x : (len(x), x))
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