how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to check if a number is even or odd in python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))wap in python to check a number is odd or even
num = int(input("Enter a number: "))
if (num % 2) == 0:
print(num ,"is even numbern")
#CODE BY VENOM STONE
else:
print(num,"is Odd numbern")
#CODE BY VENOM STONEpython odd or even
n = int(input("Enter a number: "))
print(["even","odd"][n % 2])fastest way to check odd or even in python
>>> def isodd(num):
return num & 1 and True or False
>>> isodd(10)
False
>>> isodd(9)
TrueCopyright © 2021 Codeinu
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