how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) python odd or even
n = int(input("Enter a number: "))
print(["even","odd"][n % 2])python even or odd
injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
print('This is an odd number')
else:
print('This is an even number')fastest way to check odd or even in python
>>> def isodd(num):
return num & 1 and True or False
>>> isodd(10)
False
>>> isodd(9)
TrueCopyright © 2021 Codeinu
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